Wednesday, July 22, 2015

Nomenclature Puzzle

July 22, 2015
NOMENCLATURE PUZZLE

          The goal of the activity is to engrain the ways of identifying the different types and acid formulas in our minds. We had to really dig into the periodic table and the charts to convert the formulas or written names to discover the hidden truth behind the clues. The most grandiosity of this activity was getting my mind set on the game. It was especially hard when using the information received that day and applying it to a intense and vibrant activity. My biggest contribution was when cracking at least 25% of the puzzles.




 

Tuesday, July 21, 2015

Atomic Mass of Candium

July 21, 2015

Atomic Mass of Candium


           In this lab, the students were given three variations of M&Ms (regular, peanut, pretzel). The goal was to find the Atomic Mass of the M&M. To find the Atomic Mass, the average mass of regular, peanut, and pretzel candium had to be found. I had to find the mass of all the regular, peanut, and pretzel candium isotopes, then divided by the number of isotopes in sample to find the average. Then the percent and decimal abundance had to be found to determine the average atomic mass.


The average atomic mass was 1.40.

July 21, 2015
Conclusion: 
1. Our average was 1.40. As we compared our average with another group who got 0.98, we realized our result was far greater than theirs. I would attribute this error in result due to the random choosing of combinations when scooping M&M out of the bucket.

2. I do not think it will matter whether the quantity is bigger or lesser. The number of each type of pretzels are random so the probability that you 'll get a bigger average is coincidential.

3. It would be close but not exact, because every M&M would weigh differently.

4.




Chromatography Lab

July 22, 2015












1. It is important because if the filter paper gets in direct contact with the water, then the ink will not have time to partition at its own pace. Also the final result would not be the best looking chromatogram.


2. Some of the variables that may have affected the pattern of colors may have been the marker, since each marker had a unique amount of color, especially MrSketch markers. These markers provided a variety of colors within them. Another factor may have been the amount of water and angle. The water helps reveal how much of the ink reveals while the angle dictates the direction and speed the absorbtion may have taken due to its position in the cup.


3. Black ink is made up of many different colors. For example, red, yellow, or blue can make black, but there are many other colors that can combine to form the color black. As a result, many marker  and pen companies make their black writing tools with their own combinations of black.


4. Blue is one color present in more than one type of ink. I would assume so, but I believe there would be different compounds that produce similar tones and color shades.


5. If the markers were permanent or “water-proof”, then the pens would not absorb the water and let the pigments show their colors. Solutions in which oil or other water resistant materials are soluble could be used to separate the permanent ink.



Monday, July 20, 2015

Aluminum Foil Lab

July 20, 2015
Aluminum Foil Lab


Introduction:

       In this lab, the class explored the hypothetical thickness of Aluminum foil. Given only a piece of Aluminum foil from the instructor, students had to figure out how to measure the extremely thin piece of foil through their knowledge of chemistry so far. However, first the density of aluminum had to be found via a aluminum object.


Procedure:

        To find the density, the mass and volume had to be found. To find the mass, we brought the object to the scale and found the foil was 80.3 grams. We then had to tackle the volume. To do this, we utilized the water displacement method to find the volume. By dropping the aluminum object in water and seeing how much the water rose from a set point of 250 mL told us what the volume was. The volume turned out to be 30 mL. In total, the density of Aluminum was proven to be 3 g/cm^3.

  80.3

                     Density =  --------------                               



30

            Finding the Aluminum foil was an easier deal. First we measured the two dimensional sides (9 and 9.3) to find the product of the length and width, which was 83.7. With the density given, only the mass was left to find. We took the foil to the scale and found that it was 0.49 grams. With this we were able to find the width of the foil with this equation.
                                                                          0.49


                3  =          ---------------                                 
83.7r


               R then turned out to be 0.0019 cm. Then we needed to change cm into mm, turning 0.0019 into 0.019 mm.


Conclusion:


          Overall the thickness of the aluminum foil was not that hard to find. Using the density of Aluminum foil, we were able to focus all attention to the aluminum foil itself. Replacing the thickness or height with R, we were able to form 83.7r as the total. The mass was straight forward and yielded a 0.49 grams. Together with all this information, we were able to calculate what the final thickness was. From this lab, I learned further to hone my skills in finding density, mass and volume.





Density Block Lab

7/20/15
Density Block Lab

Introduction:

      In this lab, a plastic block is being measured for the mass having limited measurements given to the tester. The testers were given the density and volume with only a ruler to find out the mass.

Procedure:

      The measurement needed was volume to complete the equation for Density which goes as shown below.






          To find the volume we measured all three properties of volume: length, width and height. Using the ruler we were able to make an accurate guess on what the real mass would be



     The given density was 0.960 and the dimensions for the plastic block was 10.1 (length), 5.3 (width), and 1.2 (height). Together multiplied became 64.236, thus allowing us to find the mass with this input.

M
           0.96            =       -----------------                                       

                                                                            64.236
      The resulting mass found was 61.7. Then it was moved to the scale to be measured and it was found to be 62.2.
      In the end there was a 0.804% error and the end result was very close to our predicted result.



Conclusion:

       The purpose of the lab was to determine the density from only the density and volume which was eventually attained through the measuring of the block. The ruler played a very crucial role in this lab, because it allowed us to investigate the lengths of the block width, length, and height. Through the discovery of the volume the mass was obtained. There might have been some mistake when it came to using the ruler to find the exact length and it may have altered the calculated mass closeness to the actual mass. In addition, the way the numbers rounded when multiplying the sides also would've affected the way the actual mass turned out. It was learned people aren't able to get the exact measure due to the tiny things beyond our sight, but I would recommend trying harder to attempt to spot the most accurate numbers possible.