Introduction:
The purpose of the lab was to identify unknown solid. To identify the solid, the mysterious substance was placed in water to obtain its solubility. Heating water to 44 degrees Celsius, the substance was placed and stirred to see if it would dissolve. Our first attempt dissolved with 3.8 grams of the substance proving that the solid was indeed not NaCl (the lowest solubility possible outcome). Then 3.2 grams were then added to the water for the second trial and it also dissolved, canceling the option of KNO3. The final answer due to elimination was NaNO3.
Procedure:
Materials- hot plates, balances, thermometer, beakers, erlemeyer flasks, stirring rods
1. Pour beaker with 10 mL
2. Put large beaker with 20 mL underneath
3. Heat water to 44 degrees C
4. Add 3.8 grams and check if it dissolves
5. If dissolved, add 3.2 grams and check if it dissolves
Data
Test #1
3.8 grams of substance- dissolved --> This canceled out the possibility of NaCl
Test #2
3.2 grams of substance- dissolved-->This canceled out the possibility of KNO3, leaving only NaNO3.
Discussion/Concluding Summary:
The substance found was NaNO3, beacause the solubility levels were on par with NaNO3 which was the only remaining possibility left. The higher the temperature, the solubility also increased.
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